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  • 16-05-2018
  • Mathematics
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find the sum 5/m^2n^2 + m/n

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11beehshahbaz 11beehshahbaz
  • 16-05-2018
Since the denominators of the two fractions are different, we need to make them same and then add the two fractions

[tex] \frac{5}{ m^{2} n^{2} } + \frac{m}{n} \\ \\ [/tex]

LCM is m²n² . So we can write:

[tex] \frac{5}{ m^{2} n^{2} } + \frac{m}{n} \\ \\ = \frac{5}{ m^{2} n^{2} }+ \frac{m(m^{2}n) }{ n(m^{2} n) } \\ \\ = \frac{5}{ m^{2} n^{2} }+\frac{m^{3}n }{ m^{2} n^{2} } \\ \\ = \frac{5+m^{3}n}{m^{2} n^{2} } [/tex]
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