amandy596 amandy596
  • 19-05-2018
  • Mathematics
contestada

Let logba=3 logbc=2 logbd=5 what is the value of logba^3d^4/c^2

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gmany
gmany gmany
  • 23-05-2018
[tex]Use:\\\log_ax+\log_ay=\log_a(xy)\\\\\log_ax-\log_ay=\log_a\dfrac{x}{y}\\\\\log_ax^n=n\cdot\log_ax[/tex]

[tex]\log_ba=3;\ \log_bc=2;\ \log_bd=5[/tex]

[tex]\log_b\dfrac{a^3d^4}{c^2}=\log_b(a^3d^4)-\log_bc^2=\log_ba^3+\log_bd^4-\log_bc^2\\\\=3\log_ba+4\log_bd-2\log_bc=3\cdot3+4\cdot5-2\cdot2=9+20-4=25[/tex]

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hillh2 hillh2
  • 21-06-2021

Answer:

25

Step-by-step explanation:

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