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When iron rusts in air iron3 oxide is produced. How many moles of oxygen react with 28.0 mol of iron in the rusting reaction 4fe(s) 3o2(g) 2fe2o3(s)

Respuesta :

McChuck
This the balanced equation based on the question [tex]4Fe + 3O_2 -\ \textgreater \ 2Fe_2O_3[/tex].

We then proceed with the following calculations

[tex]28.0molFe*(\frac {3molO_2}{4mol Fe})= 21molO_2[/tex]

The answer is [tex]21molO_2[/tex] is produced.

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