Respuesta :

sqdancefan
We presume you intend
[tex]f(x)=\dfrac{7x-9}{x-5}[/tex]
and you want to evaluate f(2).

Put 2 where x is, everywhere.
[tex]f(2)=\dfrac{7\cdot 2-9}{2-5}=\dfrac{5}{-3}=-\dfrac{5}{3}[/tex]
VictorZ
Hi there!

• f(x) = [tex]\dfrac {7x - 9}{x - 5}[/tex]

• Then,
To find th' value of f(2). Substitute " 2 " in place of " x "

f(2) = [tex]\dfrac {7 × 2 - 9}{2 - 5}[/tex]

f(2) = [tex]\dfrac {14 - 9}{-3}[/tex]

f(2) = [tex]\dfrac {5}{-3}[/tex]

f(2) = - [tex]\dfrac {5}{3}[/tex]

Hence, f(2) = - [tex]\dfrac {5}{3}[/tex]

~ Hope it helps!

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