Respuesta :

LammettHash
[tex]P(B^C)=0.71\implies P(B)=1-0.71=0.29[/tex]

[tex]P(A\cap B)=P(A)+P(B)-P(A\cup B)\implies P(A\cap B)=0.25+0.29-0.38=0.16[/tex]

[tex]P(A\mid B)=\dfrac{P(A\cap B)}{P(B)}=\dfrac{0.16}{0.29}\approx0.55[/tex]