An unopened cereal box contains 15/28 cubic foot of cereal. If the box is full, and the length and height of the box are5/7 and 1 1/2 feet, respectively, what is the width of the box?
Separate the w by diving both sides by h and l: [tex]w = \frac{v}{hl} [/tex] Then plug in the numbers: [tex]w = \frac{( \frac{15}{28}) }{( \frac{11}{2} ) \times ( \frac{5}{7}) } [/tex] Which, with the fractions flipped, equals: [tex]w = ( \frac{15}{28} ) \times ( \frac{2}{11} ) \times ( \frac{7}{5} ) \\ w = \frac{210}{1540}[/tex] [tex]w = \frac{3 \times 7 \times 10}{10 \times 2 \times 7 \times 11} \\ w = \frac{3}{2 \times 11} \\ w = \frac{3}{22} [/tex] The width of the box is 3/22 ft
