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In a sample of 100 colored​ candies, there are 21 red​ candies, 22 blue​ candies, 19 yellow​ candies, and 38 brown candies.
a. estimate the probability that when a candy is randomly​ selected, it is one that is blue.
b. the maker of the candy claims that 24​% of its candies are blue. does the estimate from part​ (a) roughly agree with this​ claim, or does there appear to be substantial​ disagreement?

Respuesta :

a. Total number of candies = 100

Red = 21, Blue= 22, Yellow= 19 and Brown= 38

Let, A is the event of selecting Blue candy

So, n(A) = 22

Total possible outcome, n(S)= 100

So, P(A) = [tex] \frac{n(A)}{n(S)} [/tex]

P(A) = [tex] \frac{22}{100} [/tex]

P(A) = 0.22 = 22%

So, the probability of selecting one candy which is blue = 22%

b. As the maker of the candy claims that 24​% of its candies are blue and 22% is close to 24%, so the estimate in part(a) roughly agree with the claim.

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