chayiljacquet
chayiljacquet chayiljacquet
  • 20-07-2018
  • Mathematics
contestada

Normal form [see attachment]

Normal form see attachment class=

Respuesta :

DeanR
DeanR DeanR
  • 20-07-2018

I just did one of these. I guessed that normal form is


[tex]x \cos \phi + y \sin \phi - p = 0[/tex]


Here' that's


[tex] x (\sqrt{3}/2) + y (1/2) - 10 = 0 [/tex]


[tex] \sqrt{3} x + y - 20 = 0[/tex]


Choice b




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