Respuesta :
Jogger moves in three displacements
d1 = 10 blocks East
d2 = 5 blocks South
d3 = 2 blocks East
now we can say
total displacement towards East direction will be
[tex]d_x = 10 + 2= 12 blocks[/tex]
Total displacement towards South
[tex]d_y = 5 block[/tex]
now to find the net displacement we can use vector addition
[tex]d = \sqrt{d_x^2 + d_y^2}[/tex]
[tex]d = \sqrt{12^2 + 5^2}[/tex]
[tex]d = 13 blocks[/tex]
so magnitude of net displacement will be equal to 13 blocks
