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20-09-2018
Mathematics

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MATH HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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20-09-2018

When x = 6, the expression on the left becomes

[tex] 4^2 + (6-3)^2 = 16 + 3^2 = 16+9=25 [/tex]

The expression on the right is

[tex] 8\cdot 4 - 4 = 32-4 = 28 [/tex]

So, the symbol you should put is

[tex] 25 < 28 [/tex]

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