ranaeemanuel27 ranaeemanuel27
  • 16-10-2018
  • Physics
contestada

A motorcycle slows down uniformly from a speed of 21 m/s to rest in 6.0s. How far did it travel during this time?

Respuesta :

skyluke89
skyluke89 skyluke89
  • 25-10-2018

Answer:

63 m

Explanation:

The initial velocity of the motorcycle is

[tex]v_i = 21 m/s[/tex]

The final velocity is

[tex]v_f = 0[/tex]

And the time taken is

[tex]t=6.0 s[/tex]

Since the acceleration of the motorcycle is uniform, we can find the distance traveled by the motorcycle during this time by using the following SUVAT equation:

[tex]S=\frac{1}{2} (v_i +v_f) t[/tex]

Substituting numbers into the equation, we find

[tex]S=\frac{1}{2}( 21 m/s + 0)(6.0 s)=63 m[/tex]

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