dezidayz10p5x2hb
dezidayz10p5x2hb dezidayz10p5x2hb
  • 19-10-2018
  • Mathematics
contestada

can someone accompany me in this equation

can someone accompany me in this equation class=

Respuesta :

allycat3345
allycat3345 allycat3345
  • 19-10-2018

Answer:

All you have to do is put it in a graphing calculator. Desmos.com is a free graphing calculator that will help you tremendously

Soulutions:

x= -.86

x= 1.67

x= 4.17

Step-by-step explanation:


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