osayuki osayuki
  • 20-10-2018
  • Mathematics
contestada

what is the square root of 225x/69#

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gmany
gmany gmany
  • 25-10-2018

[tex]\sqrt{\dfrac{225}{69}}=\dfrac{\sqrt{225}}{\sqrt{69}}=\dfrac{15}{\sqrt{69}}=\dfrac{15\sqrt{69}}{\sqrt{69}\cdot\sqrt{69}}=\dfrac{15\sqrt{69}}{69}=\dfrac{5\sqrt{69}}{23}\\\\Used:\\\\\sqrt{a}\cdot\sqrt{a}=a[/tex]

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