VincentValle15 VincentValle15

20-12-2018
Physics

contestada

A lawnmower engine running for 20 minutes does 4560000 j of work. What is the power output of the engine

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Histrionicus Histrionicus

22-12-2018

Answer:

tim e (t) = 20 min.

= 20 × 60 = 1200 s ,

Work ( W) = 4560000 J

= 4560 KJ ,

Determine:

Power output (P) = Work ÷ time

= 4560 ÷ 1200

P = 3.8 KW

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