lorenavh81 lorenavh81
  • 17-01-2019
  • Mathematics
contestada

Factor 4x^2+81 over the set of complex numbers.

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gmany
gmany gmany
  • 17-01-2019

[tex]Use:\\\\i=\sqrt{-1}\to i^2=-1\\\\a^2-b^2=(a-b)(a+b)\\--------------------\\\\4x^2+81=2^2x^2+9^2=(2x)^2-(-9^2)=(2x)^2-(-1)(9^2)\\\\=(2x)^2-(i^2)(9^2)=(2x)^2-(9i)^2=\boxed{(2x-9i)(2x+9i)}[/tex]

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Jack0000 Jack0000
  • 19-01-2022

Answer:

(2x + 9i)(2x - 9i)

Step-by-step explanation:

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