Answer:
Vertex (-3, 4); y-intercept: -5.
Step-by-step explanation:
y = -(x + 3)^2 + 4
This is the vertex form of a quadratic function whose general form is:
y = a(x - b)^2 + c where the vertex is at (b, c).
So comparing this last equation to the one in the question we see that the vertex is at (-3, 4).
When the graph passes through the y-axis x = 0 so the y intercept is calculated as follows:
y = - (0 + 3)^2 + 4
y = -9 + 4 = -5.
so the y-intercept is at (0, -5)
