machakat0
machakat0 machakat0
  • 18-01-2019
  • Mathematics
contestada

Write an equation for the line perpendicular to 6x - 7y = -8 and passes through point (-1,1).

Respuesta :

a5904640
a5904640 a5904640
  • 18-01-2019

6x - 7y = -8

-7y = -8 - 6x


Multiply everything by -1


7y = 6x + 8

y = (6x + 8)/7

y = 6x/7 + 8/7


If it's perpendicular we can say that the slope is the opposite inverse.


opposite inverse of 6/7 = -7/6


So,


(y - yo) = -7/6.(x - xo)


Now subs the point


(y - 1) = -7/6.(x - (-1))

y - 1 = -7/6.(x + 1)

y - 1 = -7x/6 - 7/6

y = -7x/6 - 7/6 + 1

y = -7x/6 + 1/6

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