Answer:
89414,89416,89418
Step-by-step explanation:
Let n bet the positive integer and then 2n is an even integer because multiplying n with 2 makes it an even integer.
Now, 2n+2, 2n+4 are the next integers.
Therefore, three consecutive integers are: 2n, 2n+2, 2n+4.
It is given that twice the first integer added to the second is 268,244 that means:
[tex]2(2n)+(2n+2)=268244[/tex]
[tex]4n+2n+2=268244[/tex]
[tex]6n=268242[/tex]
[tex]n=44707[/tex]
Therefore, three consecutive integers are:
2n=89414, 2n+2=89416, 2n+4=89418
