klina klina
  • 19-02-2019
  • Mathematics
contestada

a=(_3 2),b (4 _6),c=(5 _10)​

a3 2b 4 6c5 10 class=

Respuesta :

dastak dastak
  • 19-02-2019
first we find x of p:

[tex]x = 2 \times ( - 3) - \frac{1}{2} \times 4 + \frac{2}{5} \times 5 \\ = - 6 - 2 + 2 = - 6[/tex]

then we find y of p:

[tex]y = 2 \times 2 - \frac{1}{2} \times ( - 6) - \frac{2}{5} \times ( - 10) \\ = 4 + 3 + 4 = 11[/tex]

so

[tex]p = \binom{ - 6}{11} [/tex]

and

[tex] |p| = \sqrt{ {( - 6)}^{2} + {11}^{2} } \\ = \sqrt{36 + 121} = \sqrt{157} = 12.53[/tex]
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