nelsont21
contestada

This is my very first trig problem and I'd like to know how to tackle this. Please explain how I can do problems like these in the future!

This is my very first trig problem and Id like to know how to tackle this Please explain how I can do problems like these in the future class=

Respuesta :

Kamikazeminem

[tex] \tan(50°) = \frac{QR}{PQ} \Leftrightarrow QR = PQ \tan(50°) = 8.1 \tan(50°) \approx9.65 \\ \cos(50°) = \frac{PQ}{PR} \Leftrightarrow PR = \frac{PQ}{\cos(50°)} = \frac{8.1}{\cos(50°)} \approx12.6[/tex]

judi81

Answer:

12.6....    

explanation: