capcomplayerouqan2
capcomplayerouqan2 capcomplayerouqan2
  • 16-04-2019
  • Mathematics
contestada

Solve the system of equations: y= 3x y= x^2 - 4

Respuesta :

luisejr77
luisejr77 luisejr77
  • 16-04-2019

Answer:

[tex]x=-1\\y=-3\\\\x=4\\y=12[/tex]

Step-by-step explanation:

Make both equations equal to each other and solve for the variable x:

[tex]y=y\\3x=x^2-4\\x^2-3x-4=0\\[/tex]

Find two numbers that when you add them you get -3 and the product of both numbers be -4. These numbers are 1 and -4. Then:

[tex](x+1)(x-4)=0\\\\x+1=0\\x=-1\\\\x-4=0\\x=4[/tex]

Substitute these values into one the original equations and solve for y:

[tex]y=3(-1)\\y=-3\\\\y=3(4)\\y=12[/tex]

Therefore, you get that:

[tex]x=-1\\y=-3\\\\x=4\\y=12[/tex]

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