jsaenzrufasto70 jsaenzrufasto70

17-04-2019
Mathematics

contestada

en un triangulo rectangulo ABC (B=90) REDUCE:

J=(sec2C-cot2A) (sen2C+sen2A) es para hoy porfaaaa

Respuesta :

janthony36 janthony36

17-04-2019

Answer:

puc provar, però no sé lemme see

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