Respuesta :

[tex]\bf \stackrel{~~ solutions~\hfill }{ \begin{cases} x=7\implies &x-7=0\\ \cline{1-2} x=-5\implies &x+5=0 \end{cases}}\qquad \implies \stackrel{\textit{factored form}}{y=(x-7)(x+5)}[/tex]

Answer:

y = (x - 7)(x + 5)

Step-by-step explanation:

Given the solutions are x = 7 and x = - 5 then the factors are

(x - 7) and (x + 5)

The quadratic equation is the product of the factors

(x - 7)(x + 5) = 0 ← in factored form

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