Answer:
a=-2
b=4
c=-3
Step-by-step explanation:
You just compare -2x^2+4x-3=0 to
ax^2+bx+c=0
There is really no work here.
For this case we have that by definition, a quadratic equation is of the form:
[tex]ax ^ 2 + bx + c = 0[/tex]
The roots are given by:
[tex]x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}[/tex]
We have the following equation:
[tex]-2x ^ 2 + 4x-3 = 0[/tex]
So:
[tex]a = -2\\b = 4\\c = -3[/tex]
Answer:
[tex]a = -2\\b = 4\\c = -3[/tex]
