Answer:
F(x)=4x and g(x) =3x
Step-by-step explanation:
We will have to check each pair of functions one by one
So,
For f(x)=3-4x and g(x)=16x-3
For composition we have to put g(x) in place of x in f(x)
(fog)(x)=3-4(g(x))
= 3-4(16x-3)
=3-64x+12
=-64x+15
So first pair doesn't give 12x.
Now for,
F(x)=6x2 and g(x)= 2/x
(fog)(x)= 6(g(x))^2
=6(2/x)^2
=6*(4/x^2)
=24/x^2
For the last pair:
F(x)=4x and g(x) =3x
(fog)(x)=4(g(x))
=4(3x)=12x
So for the last pair of functions (fog)(x) is 12x ..
