lemuelsp9928 lemuelsp9928
  • 18-07-2019
  • Mathematics
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Exercise 2.1.47 Prove that ifA^-1 exists and AX=0 then X =0.

Respuesta :

presipao
presipao presipao
  • 31-07-2019

Answer:

Step-by-step explanation:

If [tex]A^{-1}[/tex] exist, then we have that [tex]A^{-1}\cdot A=1[/tex].

Therefore, in the case that [tex]AX=0[/tex], if we multiply both

terms in the equation by [tex]A^{-1}[/tex], then we have

[tex]A \cdot A^{-1}X=A^{-1}0[/tex]

and so the equation tells us that

[tex]X=A\cdot A^{-1}X=A^{-1}0=0[/tex].

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