A material having an index of refraction of 1.35 is used as an antireflective coating on a piece of glass (n = 1.50). What should be the minimum thickness of this film in order to minimize reflection of 560 nm light?

Respuesta :

Answer:

103.70 nm

Explanation:

The minimum thickness of the film is given by [tex]t=\frac{\lambda }{4n}[/tex] where [tex]\lambda[/tex] is the wavelength and n is the index of the refraction

We have n =1.35

Wavelength [tex]\lambda =560nm[/tex]

So the minimum thickness of the film [tex]t=\frac{\lambda }{4n}=\frac{560}{4\times 1.35}=103.70\ nm[/tex]