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While rearranging a dorm room, a student does 310 J of work in moving a desk 2.9 m. What was the magnitude of the applied horizontal force?

Respuesta :

Answer:

The horizontal force is 106.89 N.

Explanation:

Given that,

Work done = 310 J

Distance = 2.9 m

We need to calculate the horizontal force

Using formula of work done

[tex]W= Fd\cos\theta[/tex]

Where, [tex]\theta=0^{\circ}[/tex]

[tex]W=F\cdot d[/tex]

Put the value into the formula

[tex]310=F\cdot 2.9[/tex]

[tex]F=\dfrac{310}{2.9}[/tex]

[tex]F=106.89\ N[/tex]

Hence, The horizontal force is 106.89 N.

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