[tex]\bf \begin{array}{ccll} loads&tons\\ \cline{1-2} 6&\frac{2}{3}\\\\ 1&x \end{array}\implies \cfrac{6}{1}=\cfrac{~~\frac{2}{3}~~}{x}\implies 6=\cfrac{~~\frac{2}{3}~~}{\frac{x}{1}}\implies 6=\cfrac{2}{3}\cdot \cfrac{1}{x} \\\\\\ 6=\cfrac{2}{3x}\implies 18x=2\implies x=\cfrac{2}{18}\implies x=\cfrac{1}{9}[/tex]
Algebraic equations are equations where we can solve for unknown variables.
The weight of 1 load of stone is [tex]\frac{1}{9}[/tex] ton.
From the question:
6 loads of stone = [tex]\frac{2}{3}[/tex] ton
1 load of stone = ?
Cross Multiply
1 load x [tex]\frac{2}{3}[/tex] ton / 6 loads
= [tex]\frac{2}{3}[/tex] ÷ [tex]\frac{6}{1}[/tex]
= [tex]\frac{2}{3}[/tex] × [tex]\frac{1}{6}[/tex]
= [tex]\frac{1}{9}[/tex]
Therefore, the weight of 1 load of stone is [tex]\frac{1}{9}[/tex] ton.
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