MalcolmHarris MalcolmHarris
  • 16-05-2016
  • Mathematics
contestada

find the value or values of x in the quadratic equation x2=6x-9.

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GreenEyes71
GreenEyes71 GreenEyes71
  • 16-05-2016

x² = 6x - 9, or x² - 6x + 9 = 0, or x² - 2*x*3 + 3² = 0, or (x-3)² = 0 => x₁ = x₂ = 3.

Green eyes.

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garydesir1
garydesir1 garydesir1
  • 16-05-2016

Hi Harris


x²=6x-9

First thing we need to do is

subtract 6x-9 from the booth sides

x²-(6x-9)=6x-9-(6x-9)

x²-6x+9=0

Now we gonna factor the left side

(x-3)(x-3)=0

Set factor equal 0

x-3=0 or x-3=0

x=3


I hope that's help !

Answer Link

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