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A cylindrical glass tube 10.3 cm in length is filled with mercury (density = 13.6 g/mL). (The volume of a
cylinder of radius r and length his V = arh.) The mass of mercury needed to fill the tube is 106.3 g.
Calculate the inner diameter of the tube.
cm

Respuesta :

Neetoo

Answer:

0.982 cm

Explanation:

Given data:

Density= 13.6 g/mL

mass= 106.3 g

volume = ?

Formula:

d=m/v

v= m/d

v= 106.3 g/ 13.6 g/mL

v= 7.816 mL

Now we have to find the radius of tube:

Formula:

V= πr²h

v= 7.816 ml

π= 22/7 = 3.14

h= 10.3 cm

now we will put the values in formula:

V= πr²h

7.816 mL= 3.14× r² × 10.3 cm

7.816/ 32.342 = r²

r² = 0.242 mL/cm

r= 0.491 cm

Formula for diameter is given below:

diameter= 2× radius

diameter= 2× 0.491 cm

diameter= 0.982 cm

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