Answer:
c. 0.026
Explanation:
Suppose the population is in Hardy-Weinberg equilibrium. According to it,
p + q = 1
p² + 2pq + q² = 1
where p= frequency of dominant allele
q = frequency of recessive allele
p² = frequency of homozygous dominant genotype
q² = frequency of homozygous recessive genotype
2pq = frequency of heterozygous genotype
Here, q = w = 0.84
p = W = 1 -w = 1- 0.84= 0.16
W² = 0.16 * 0.16 = 0.0256 = 0.026
Hence, frequency of the homozygous dominant genotype = 0.026
