Answer:
(a) Acceleration [tex]a=2m/sec^2[/tex]
(b) Distance s = 25 m
Explanation:
We have given constant force F = 2000 N
Mass of the car = 1000 kg
(a) From newton's law we know that F = ma
So [tex]2000=1000\times a[/tex]
[tex]a=2m/sec^2[/tex]
(b) Tine is given as t = 5 sec
As the car is initially at rest so initial velocity u = 0 m/sec
From second equation of motion [tex]s=ut+\frac{1}{2}at^2[/tex]
So [tex]s=0\times 5+\frac{1}{2}\times 2\times 5^2=25m[/tex]
