angelbaby82
angelbaby82 angelbaby82
  • 17-10-2019
  • Mathematics
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X^2 (4x - 5) (7x - 13)= 0

Pleaseeee helppppp

Respuesta :

jimrgrant1 jimrgrant1
  • 17-10-2019

Answer:

see explanation

Step-by-step explanation:

To solve

x²(4x - 5)(7x - 13) = 0 ← in standard form

Equate each of the factors to zero and solve for x

x² = 0 ⇒ x = 0 with multiplicity 2

4x - 5 = 0 ⇒ 4x = 5 ⇒ x = [tex]\frac{5}{4}[/tex]

7x - 13 = 0 ⇒ 7x = 13 ⇒ x = [tex]\frac{13}{7}[/tex]

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