Answer:
[tex]\Delta x = 0.68 m[/tex]
Explanation:
As we know that limit of resolution of two objects is given as
[tex]\Delta x = L(\frac{1.22 \lambda}{a}[/tex]
here we have
L = distance of the car from the eye
[tex]L = vt[/tex]
[tex]L = 25.3 \times (1.93 \times 60)[/tex]
[tex]L = 2929.74 m[/tex]
[tex]\lambda = 650 nm[/tex]
[tex]a = 3.4 mm[/tex]
now we have
[tex]\Delta x = 2929.74( \frac{1.22 \times 650 \times 10^{-9}}{3.4 \times 10^{-3}})[/tex]
[tex]\Delta x = 0.68 m[/tex]
