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Calculate the conductance of a conduit whose cross-sectional area is 2.0 cm2 and whose length is 9.0 cm if its conductivity is 0.70 ohm-1cm-l. G = _____ ohm-1 0.32 0.31 0.16 6.4

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opudodennis

Answer:

[tex]0.16 ohm^{-1}[/tex]

Explanation:

Cell constant, k is given by, [tex]k={L}{A}[/tex] where L is length and A is area. Substituting A for [tex]2 cm^{2}[/tex] and L for 9 cm we obtain

[tex]k=\frac {9}{2}=4.5 cm^{-1}[/tex]

Conductance, C is given by dividing conductivity by cell constant hence

[tex]C=\frac {R}{k}[/tex]

Substituting 0.7 for R we obtain

[tex]C=\frac {0.7}{4.5}= 0.155555556 ohm^{-1}\approx 0.16 ohm^{-1}[/tex]

Answer:

G = 0.16

Explanation:

G=0.7/(9/2)

G=0.16

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