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Suppose the distribution of the daily calcium intake of Americans is left skewed with a mean of 800 mg and a standard deviation of 16 mg. What can we say about the sampling distribution of distribution X?

a. The mean of the sampling distribution of X is 800.


b.The standard deviation of the sampling distribution of X is 16.


c.The value of every sample mean is 800The sampling distribution of X will be approximately normal regardless of sample size.

Respuesta :

Answer:

a. The mean of the sampling distribution of X is 800.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], a large sample size of the sampling distribution can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

So, the correct answer is

a. The mean of the sampling distribution of X is 800.

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