The value of y when x = 5 is 45
Given that y varies directly with x. This can be written mathematically as:
y ∝ x
[tex]y = k \times x[/tex] ---- eqn 1
Where "k" is the constant of propotionality
Given y = 27 when x = 3. Substitute these values in eqn 1
[tex]27 = k \times 3\\\\k = \frac{27}{3} = 9[/tex]
Substitute k = 9 in eqn 1
y = 9x ----- eqn 2
To find: y = ? and x = 5
Substitute x = 5 in eqn 2
[tex]y = 9 \times 5 = 45[/tex]
Thus the value of y when x = 5 is 45
