Answer:
Normal force of 10,000N
Explanation:
From the question, the weight the car exerts on the pavement is 10,000N.
The pavement exerts upward and perpendicular contact force called normal force on the car to support its weight. Also, the normal force is equal and opposite to the weigh of the car.
Hence the pavement exerts normal force of 10,000N back on the car to prevent it from passing through it.
