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The length,AB of the rectangular lot is 1 foot less than two times its width, BC. If the perimeter of the rectangular lot 394 feet, what is the length, AB of the rectangular lot?

Respuesta :

calculista

Answer:

[tex]AB=131\ ft[/tex]

Step-by-step explanation:

we know that

The perimeter of the rectangular lot is

[tex]P=2(AB+BC)[/tex] ----> equation A

where

AB is the length

BC is the width

we have

[tex]AB=2BC-1[/tex] ---> equation B

[tex]P=394\ ft[/tex] ----> equation C

substitute equation B and equation C in equation A

[tex]394=2(2BC-1+BC)[/tex]

solve for BC

[tex]394=2(3BC-1)[/tex]

[tex]394=6BC-2[/tex]

[tex]6BC=396[/tex]

[tex]BC=66\ ft[/tex]

Find the value of AB

[tex]AB=2BC-1[/tex]

[tex]AB=2(66)-1[/tex]

[tex]AB=131\ ft[/tex]

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