Answer:
36.87°
Explanation:
length of anchor (L) = 30 m
depth of water (d) = 18 m
find the angle of depression the anchor chain makes with the water level
from the diagram attached the anchor chain, the water bed and the depth of the water all form a right angle triangle
therefore
cos θ = [tex]\frac{d}{L}[/tex]
cos θ = [tex]\frac{18}{30}[/tex]
θ = [tex]cos^{-1}.\frac{18}{30}[/tex] = 53.13°
the angle of depression (Ф) = 90 - 53.13 = 36.87°
