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Carbon disulfide is produced by the reaction of carbon and sulfur dioxide. What is the percent yield of carbon disulfide if the reaction of 40.0 g of carbon produces 36.0 grams of carbon disulfide? (3 pts)

5C + 2SO2 --> CS2 + 4CO

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Answer:

The percent yield of carbon disulfide is 78.8%

Explanation:

Percent yield of reaction = (Produced yield / Theoretical yield) . 100

5C + 2SO₂ --> CS₂ + 4CO

In the reaction 5 moles of C, produce 1 mol of CS₂

40 g / 12 g/m = 3.33 moles

Then, this is the rule of three:

5 mol of C produce 1 mol of CS₂

3.33 moles of C, will produce ( 3.33  .1)/5 = 0.666 moles

Mol . molar mass = mass →  0.666 mol . 76.12 g/m =50.7 g (Theoretical yield)

(40 g / 50.7 g) . 100 = 78.8%

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