Answer:
d) 4a
Explanation:
r = Distance
Electrostatic force is given by
[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]
[tex]ma=\dfrac{kq_1q_2}{r^2}[/tex]
It can be seen that the force is inversely proportional to distance
[tex]a\propto \dfrac{1}{r^2}[/tex]
If the distance is reduced
[tex]\dfrac{a_1}{a_2}=\dfrac{r_2^2}{r_1^2}\\\Rightarrow \dfrac{a_1}{a_2}=\dfrac{(\dfrac{d}{2})^2}{d^2}\\\Rightarrow \dfrac{a_1}{a_2}=\dfrac{1}{4}\\\Rightarrow a_2=4a_1[/tex]
So, the new acceleration will be four times the old acceleration
The answer is d) 4a
