saijuchacko saijuchacko
  • 20-01-2020
  • Mathematics
contestada

Length of a rectangle is 4x²+12x and the area of the rectangle is 24x⁴+72x³, what is the width of the rectangle?

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kudzordzifrancis
kudzordzifrancis kudzordzifrancis
  • 01-02-2020

Answer:

The width is [tex]6x^2[/tex]

Step-by-step explanation:

The area of a rectangle is given as : [tex]Area=l\times w[/tex]

This implies that: [tex]w=\frac{Area}{l}[/tex]

We have that the length is [tex]l=4x^2+12x[/tex] and the area is [tex]Area=24x^4+72x^3[/tex]

We substitute to get:

[tex]w=\frac{24x^4+72x^3}{4x^2+12x}[/tex]

[tex]\implies w=\frac{24x^2(x^2+3x)}{4(x^2+3x)}[/tex]

We cancel out the common factors to get:

[tex]w=6x^2[/tex]

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