Answer:
Explanation:
Given
Barometric reading [tex]h_{g}=754\ mm\ of\ Hg[/tex]
The above value is pressure head, so converting into Pressure
[tex]P=\rho \times g\times h[/tex]
where [tex]\rho =[/tex]density of mercury
g=acceleration due to gravity
h=height
[tex]P=13.6\times 10^3\times 9.8\times 0.754[/tex]
[tex]P=100.49\ kPa[/tex]
