Answer: 114.4 GJ
Explanation:
Heat loss Q=U×A×ΔT
Heat loss of size A is determined by the U value of materials and the difference in temperature.
From 10.9cm from the ice
50m= 5000cm
A= 5000×5000
Q== (10.9) (5000) (5000)(4.184)(1×4 + 80)
Q = 95,771,760,000J
Q≈ 95.8 GJ
Linear gradient from the bottom of the pond to the ice:
Q = (89.1)(5000)(5000)(4.184)(1*2)
Q = 18,639,720,000J
Q ≈ 18.6 GJ
Total heat loss:
Q= 95.8GJ + 18.6GJ
Q= 114.4 GJ
