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To study the properties of various particles, you can accelerate the particles with electric flelds. A positron is a particle with the same mass as an electron but the opposite charge (+e). Express your answer in vector form. Do not enter units in your expression (a) If a positron is accelerated by a constant electric field E - (320 1 - 125j-195 kN/C, find the acceleration of the positron (32-125j-15d th m/s2 (b) Assuming the positron started from rest, find the velocity of the positron 8.75 x 10-9 s later. m/s

Respuesta :

Answer:

Explanation:

When a charge q is placed in an electric field , a force equal to qE acts on it

Force on positron

= 1.6 x 10⁻¹⁹ x ( 320 i - 125 j - 195 k ) N

Acceleration

= force / mass

= 1.6 x 10⁻¹⁹ x ( 320 i - 125 j - 195 k ) / 9.1 x 10⁻³¹

a = 1.76 x 10¹¹ ( 320 i - 125 j - 195 k )

b )

velocity

= u + at

= 1.76 x 10¹¹ ( 320 i - 125 j - 195 k ) x 8.75 x 10⁻⁹

= 15.4 x 10²( 320 i - 125 j - 195 k )

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