hannahbeccahxo7213 hannahbeccahxo7213
  • 19-02-2020
  • Chemistry
contestada

A 155-L helium balloon is heated from 24.0 C to 38.0 C. What would be its new volume assuming the pressure remains constant?

Respuesta :

abiolaraymond1995
abiolaraymond1995 abiolaraymond1995
  • 20-02-2020

Answer:

New volume is 162.3 L

Explanation:

We will use Charles law to solve this problem. It states that the volume of a fixed mass of gas is directly proportion to its kelvin temperature, provided pressure is kept constant. Its mathematically represented below.

[tex]\frac{V_{1} }{T_{1} } =\frac{V_{2} }{T_{2} }[/tex]

from the question;

V1=155L  

T1=24°C =24+273 =297K  

T2=38°C=38+273 = 311K

V2=?

[tex]V_{2}= \frac{V_{1}T_{2} }{T_{1} }[/tex]

[tex]V_{2}=\frac{155*311}{297}[/tex]

V2=162.3 L

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