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If 32.146g of MgSO4 is added to enough water to make 100.00mL solution, what is the molarity of MgSOA? noles solute Liters of solution
O 2.6706 M
O 3.7445M
O 0.037445
O 0.0026706 M
O 3869.4 M

Respuesta :

joseaaronlara

Answer:

The answer to your question is 2.68 M

Explanation:

Data

mass of MgSOâ‚„ = 32.146 g

volume of water = 100 ml

Molarity = ?

Formula

Molarity = moles / volume

Process

1.- Calculate the molar mass of MgSOâ‚„

MgSOâ‚„ = 24 + 32 + (16 x 4) = 120 g

2.- Calculate the number of moles of MgSOâ‚„

                     120 g --------------------- 1 mol

                    32.146 g ------------------ x

                     x = (32.146 x 1) / 120

                     x = 0.268 moles

3.- Calculate molarity

Molarity = 0.268 / 0.1

Molarity = 2.68

Molar concentration is a measure of the concentration of a chemical species, in particular of a solute in a solution, in terms of the amount of substance per unit volume of solution.

The closest answer to this question is 2.68 M.

All the data are given in the question and these data is as follows:-

  • Mass of [tex]MgSO_4[/tex] = [tex]32.146 g[/tex]
  • The volume of water = 100 ml

We have to find the molarity, so the formula we are gonna use is:-

[tex]Molarity = \frac{moles}{volume}[/tex]

The molar mass of [tex]MgSO_4 , MgSO_4[/tex][tex]= 24 + 32 + (16 * 4) = 120 g[/tex]

After calculation, the number of moles is equal to:-  

              [tex]x = \frac{(32.146 * 1)}{120} x = 0.268 moles[/tex]      

To find the molarity,  [tex]\frac{0.268}{0.1}[/tex]  [tex]=2.68[/tex]

Hence the closest option is A.

For more information, refer to the link:-

https://brainly.com/question/2817451

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