williamdford99 williamdford99
  • 20-02-2020
  • Physics
contestada

A 5.5 kg box is pushed across the lunch table. the net force applied to box is 9.7 N. what is the acceleration of the box?

Respuesta :

Onoriodefelix
Onoriodefelix Onoriodefelix
  • 20-02-2020

Answer:

a = 1.76m/s^2

Explanation:

Force = mass x acceleration

F = m x a

N = kg x m/s^2

From the question

m = 5.5kg

F = 9.7N

Therefore,

Using the above formula

9.7 = 5.5 x a

9.7 = 5.5a

Divide both sides by 5.5

9.7/5.5 = 5.5a/5.5

1.76 = a

a = 1.76m/s^2

Answer Link
michellecarrascono2
michellecarrascono2 michellecarrascono2
  • 12-01-2021

Answer:it’s 1.76m/s^2

Explanation:

Right

Answer Link

Otras preguntas

How did James Oglethorpe, the founder of Georgia, treat the local American Indians? Oglethorpe released them from enslavement and forced labor. Oglethorpe provi
How is jrotc different from now then 100 years ago?
What is 93 divided by 3 in repeated subtraction
Around 1900, European nations built up their military forces, formed alliances, and expanded their colonial holdings in their efforts to
Can two different samples of the same substance have different physical properties? Chemical properties?
seven divided by one sixth
which russian revolution led to the creation of the duma?
What is the subject in this simple sentence? Marsupials are an interesting group of mammals. a. Marsupials b. are c. mammals d. group
How can you help to prevent muscle mass loss as you age?
Find the product 6×500=6×blank hundreds